https://api.playposit.com/player_v2/?type=share&bulb_id=1323635&lms_launch=true
In a chemical reaction, one or more reactants are transformed into products:
reactants → products
The purpose of a chemical equation is to express this relation in terms of the formulas of the actual reactants and products that define a particular chemical change. For example, the reaction of mercury with oxygen to produce mercuric oxide would be expressed by the equation
Hg + O2 → HgO
Sometimes, for convenience, it is desirable to indicate the physical state (gas, liquid or solid) of one or more of the species by appropriate abbreviations:
Hg(l) + O2(g) → HgO(s)
C(graphite) + O2(g) → CO2(g)
C(diamond) + O2(g) → CO2(g)
However, this is always optional.
Chemical equations must be balanced!
Basically, this means that chemical equations must be consistent with the law of conservation of mass:
Figure 4.10 Combustion Reaction
Ref: commons.wikimedia.org/
In the context of an ordinary chemical reaction, conservation of mass means that atoms are neither created nor destroyed. This requirement is easily met by making sure that there are equal numbers of all atoms on both sides of the equation.
When we balance an equation, we simply make it consistent with the observed fact that individual atoms are conserved in chemical changes.
A chemical Equation is made of reactants at the left side of the chemical equation. These reactants are compounds being reacting to produce new compounds called the products at right side of the chemical equation Both reactants and products are separated with an arrow.
If the reaction goes mostly to completion, then one arrow is used but if the reaction does not go to completion, then double arrows are used which means that both the reactants and the products are found in reaction in appreciative amount at the end of the reaction and the reaction does not give only products.
Figure 4.11 Balancing Chemical Requation
Ref: commons.wikimedia.org/
Reaction goes to completion: (Using One Arrow to Separate the Reactants from the Products)
Here are few more examples:
Figure 4.12 Balancing Chemical Equation
Ref: commons.wikimedia.org/
Some Reactions do not go to completion also known as chemical equilibrium: (Using Double Arrows to Separate the Reactants from the Products)
Figure 4.13 Chemical Equation
Ref: commons.wikimedia.org/
Furthermore, one to differentiate between numbers of moles (also called coefficients) appearing at the front of the products or the reactants which are changed till the chemical equations are balanced, and the numbers appearing within the molecular formula as subscripts which are fixed and should not be touched when balancing chemical equations.
Example:
General Procedure to balance chemical equation:
Example:
C4H10 + O2 à CO2 + H2O + Heat
Let us make a table:
Number of Atoms or Number of Polyatomic Anions | Number of Atoms or Number of Polyatomic AnionsLeft Side (Reactants’ Side) | Number of Atoms or Number of Polyatomic AnionsRight Side (Products Side) | Status of the Balancing |
C atom | 4 | 1 | Not Balanced |
H atom | 10 | 2 | Not Balanced |
O atom | 2 | 3 | Not Balanced |
Now let us multiply the Carbon atom at the right side by 4 and Hydrogen atom by 5 to balance them at both sides.
C4H10 + O2 à 4 CO2 + 5 H2O + Heat
Number of Atoms or Number of Polyatomic Anions | Number of Atoms or Number of Polyatomic AnionsLeft Side (Reactants’ Side) | Number of Atoms or Number of Polyatomic AnionsRight Side (Products Side) | Status of the Balancing |
C atom | 4 | 4 | Balanced |
H atom | 10 | 10 | Balanced |
O atom | 2 | 13 | Not Balanced |
Now look at the chemical reaction. Everything is balanced except oxygen. General rule of thumb; if one atom at one side has an even number (i.e. like oxygen atom at the left side 2) and odd number at the other side (i.e. like oxygen atom at the right side 130, one has to go through fraction to balance the chemical equation:
C4H10 + 13/2 O2 à 4 CO2 + 5 H2O
Since nature does not support fractional atoms, both side of the chemical equations have to be multiplied with the denominator which is 2:
2 x [C4H10 + 13/2 O2 à 4 CO2 + 5 H2O
The final balance chemical equation is then:
2 C4H10 + 13 O2 à 8 CO2 + 10 H2O
Practice: try this one!
Figure 4.14 Balancing Chemical Equation
Ref: commons.wikimedia.org/
What are the coefficients of the balanced equation of the above equation?
Try this Balancing app(free): “Reactions” with more than 400 equations for practicing balancing. Look for the app in app store on any mobile device.
Figure 4.15 Balancing App
Ref: commons.wikimedia.org/
In case of polyatomic ion containing equations, it is always recommended to consider them as unit rather than broken down to individual atoms if they appear on both sides of the equation.
LiOH + H3PO4 → Li2HPO4 +H2O (unbalanced)
To balance Li, we have to put coefficient 2 in front of LiOH. That will give total number H on the left hand side= 5 and O=2, keeping PO4 unit separate from other elements. We can put coefficient 2 in front of H2O to form 4 H and 2 O, remaining one H is present in Li2HPO4. PO4 unit is same on left and right hand side. So the final number of atoms look like :
Left side: Li -2 Right side: Li-2
O-2 O-2
H-5 H-5
PO4-1 PO4-1
Balanced equation is
2LiOH + H3PO4 → Li2HPO4 +2H2O (balanced)
Always lowest number of coefficients are used to balance a chemical equation. For example, 2H2O → 2H2 + O2, this equation can also be balanced by 4H2O → 4H2 + O2
But we always use lowest set of whole numbers to balance an equation.
The following video might help you to understand more this topic.
Now let us review the videos below:
Balancing Chemical Equations Practice Problems
Introduction to Balancing Chemical Equations
Balancing Chemical Equations Step by Step Practice Problems | How to Pass Chemistry
Chemical equations should exhibit the status of the chemical compounds involved in the chemical reactions such liquids (l), solids (s), gases (g) and aqueous (aq).
Furthermore, the status of the heat being absorbed (taken in) or given away:
2 C4H10(g) + 13 O2(g) …..> 8 CO2(g) + 10 H2O(g) + Heat [Exothermic]
HgCO3(s) ∆ HgO(s) + CO2(g) [Exothermic]
Heat + NH4Cl(g) …..> NH3(g) + HCl(g) [Endothermic]
The chemical equations of ionic compounds in aqueous solution (dissolved in water) represent very unique sets of balancing:
Complete molecular ionic chemical equation:
This is an ionic chemical equation that keeps the ionic compounds and they are not taken apart in ions.
Example:
NaI(aq) + Pb(NO3)2(aq) …..> PbI2(s) + NaNO3(aq)
Balancing this molecular ionic chemical equation:
2 NaI(aq) + Pb(NO3)2(aq) ….> PbI2(s) + 2 NaNO3(aq)
Complete ionic chemical equation:
Each aqueous ionic compound in the ionic chemical equation will be taken apart to its original ions, keeping all solids, liquids and gaseous compounds untouched:
2 NaI(aq) + Pb(NO3)2(aq) …..> PbI2(s) + 2 NaNO3(aq)
Figure 4.16 Precipitation Reaction
Reference: https://microbenotes.com/introduction-to-precipitation-reaction/
The videos below illustrate the net ionic chemical equations set up and balancing:
Molecular, Ionic, and Net Ionic Equations
How to Write Complete Ionic Equations and Net Ionic Equations
The simulation below helps understand the concept of balancing chemical equation:
Learning Goals: Students will be able to:
Develop your understanding: Open the Introduction screen, then explore to develop your own ideas about what it means to “balance a chemical equation”.
Explain your understanding:
Test your understanding: For each question, write your answer and give your reasoning with evidence from the simulation.
Question 1
Your answer and explanation:
Question 2
Your answer and explanation:
Question 3
Your answer and explanation:
Question 4
Your answer and explanation:
Question 5
Your answer and explanation:
Test your understanding and skill application:
Open the full simulation Balancing Chemical Equations, then open the Game screen. Use ideas you have from the learning goals. You may need to use the Intro and Balance Lab screens to learn.
Final Score:
After you play all levels of the game. Copy and paste your final results like this
Extra challenge: For an extra challenge, you can turn on the timer and see if you can improve your skills.