Gas Collected Over Water
Figure 9.58 Gas collected over water
Ref: commons.wikimedia.org/
The law of partial pressure is frequently used to determine the yield of a water-insoluble gas formed in a reaction. The gaseous product bubble through the water and is collected into an inverted container. The water vapor that mixes with the gas contributes a portion of the total pressure, called the vapor pressure, which depends only on the water temperature.
Ptotal- PH2O= Pgas
Apply PV/RT to find the moles
Knowing the molar mass, find the mass of the gas
Figure 9.59 An apparatus for collecting Gases by the displacement of water
Ref: commons.wikimedia.org/
When KClO3(s) is heated, O2 is produced according to the equation . The oxygen gas travels through the tube, bubbles up through the water, and is collected in a bottle as shown.
The only gases that cannot be collected using this technique are those that readily dissolve in water (e.g., NH3, H2S, and CO2) and those that react rapidly with water (such as F2 and NO2). Remember, however, when calculating the amount of gas formed in the reaction, the gas collected inside the bottle is not pure. Instead, it is a mixture of the product gas and water vapor. As we know all liquids (including water) have a measurable amount of vapor in equilibrium with the liquid because molecules of the liquid are continuously escaping from the liquid’s surface, while other molecules from the vapor phase collide with the surface and return to the liquid. The vapor thus exerts a pressure above the liquid, which is called the liquid’s vapor pressure. In the case shown above, the bottle is therefore actually filled with a mixture of O2 and water vapor, and the total pressure is, by Dalton’s law of partial pressures, the sum of the pressures of the two components:
If we want to know the pressure of the gas generated in the reaction to calculate the amount of gas formed, we must first subtract the pressure due to water vapor from the total pressure. This is done by referring to tabulated values of the vapor pressure of water as a function of temperature. As shown in figure below, the vapor pressure of water increases rapidly with increasing temperature, and at the normal boiling point (100°C), the vapor pressure is exactly 1 atm. The methodology is illustrated in Example 14.
Table 10.4 Vapor Pressure of Water at Various Temperatures
T (°C) | P (in mmHg) | T | P | T | P | T | P |
0 | 4.58 | 21 | 18.66 | 35 | 42.2 | 92 | 567.2 |
5 | 6.54 | 22 | 19.84 | 40 | 55.4 | 94 | 611.0 |
10 | 9.21 | 23 | 21.08 | 45 | 71.9 | 96 | 657.7 |
12 | 10.52 | 24 | 22.39 | 50 | 92.6 | 98 | 707.3 |
14 | 11.99 | 25 | 23.77 | 55 | 118.1 | 100 | 760.0 |
16 | 13.64 | 26 | 25.22 | 60 | 149.5 | 102 | 815.8 |
17 | 14.54 | 27 | 26.75 | 65 | 187.7 | 104 | 875.1 |
18 | 15.48 | 28 | 28.37 | 70 | 233.8 | 106 | 937.8 |
19 | 16.48 | 29 | 30.06 | 80 | 355.3 | 108 | 1004.2 |
20 | 17.54 | 30 | 31.84 | 90 | 525.9 | 110 | 1074.4 |
Figure 9.60 A Plot of the Vapor Pressure of Water versus Temperature
Ref: commons.wikimedia.org/
The vapor pressure is very low (but not zero) at 0°C and reaches 1 atm = 760 mmHg at the normal boiling point, 100°C.
Practice Problems